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Many LED bulbs and spotlights require 12V to power them, which requires you to buy or obtain a power source from somewhere. In fact, you can make it yourself using inexpensive parts.
The simplest transformerless power supply for an LED matrix

Materials:


  • LED Matrix 12V 5W.
  • 4 diodes 1N4007;
  • ceramic capacitor 1 μF, voltage not lower than 400 V;
  • 1 resistor in the range of 300 kOhm - MOhm;
  • capacitor 220 uF 25 V;
  • electrical cable with plug.

Assembly of a transformerless source


The simplest transformerless power supply for an LED matrix

First you need to solder 4 1N4007 diodes together, according to the circuit as in the photo. Pay attention to the polarity. It is important that the direction of the anode and cathode are as in the photograph. Beginning radio enthusiasts just need to follow the gray strip around the circumference of the diode body. As you can see, one pair of them is connected stripe to stripe, and the second with dark sides. Accordingly, the pairs are soldered together by a strip to the plain side.
The simplest transformerless power supply for an LED matrix

For a 220 uF 25 V capacitor, you need to bend the contacts and solder them to a frame of diodes. There is a longitudinal stripe on its body.The electrode opposite to it is soldered to the contacts of the diodes connected strip to strip. The contact adjacent to the mark is fastened accordingly to the diodes on the side opposite to the stripes.
The simplest transformerless power supply for an LED matrix

Next, a 1 µF ceramic capacitor (105J) is soldered to the existing circuit with one tendril. To do this, it should be placed on the left hand and turned with the marking towards you.
The simplest transformerless power supply for an LED matrix

A 1 MΩ resistor is soldered between the antennae of the ceramic capacitor. It has no polarity, so it can be placed on either side. This resistor is needed to discharge the capacitor when power is disconnected from the entire circuit.
The simplest transformerless power supply for an LED matrix

The consumer is connected to the circuit. In this case, a 12 V and 5 W LED matrix is ​​used.
The simplest transformerless power supply for an LED matrix

In order for it to shine, you need to maintain the polarity. The minus is connected to the electrodes on the side of the strip on a 220 uF 25 V capacitor. The plus is soldered opposite.
The simplest transformerless power supply for an LED matrix

To power the circuit from a 220V network, you need to connect a two-core cable with a plug. One core is soldered to the electrode of a ceramic capacitor and resistor, and the second to the unused opposite part of the diode frame.
The simplest transformerless power supply for an LED matrix

We plug it into the network.
The simplest transformerless power supply for an LED matrix

Works great.

Important! Safety precautions


This is a very cheap power source to manufacture. LEDs and their matrices, but it has one very significant drawback: you cannot touch it so as not to receive a 220 V discharge, since the entire circuit does not have galvanic isolation. Therefore, this homemade product may not be suitable for everyone.
The finished source must be placed in a box made of dielectric material. During operation, it is forbidden to even touch the LED matrix; be sure to take this into account.

Watch the video


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Comments (6)
  1. Alexander_57
    #1 Alexander_57 Guests 23 July 2019 13:21
    4
    Judging by the appearance, a 10-watt LED matrix is ​​used. It is used at 0.8 W, i.e., at a current of about 66 mA, due to the choice of the value of capacitance C1.
    For such matrices on a radiator, it is more appropriate to choose a ballast capacitance of about 10 μF, and this will be with a margin. But the brightness will increase very significantly.
    It would be nice to increase the capacitance C2 by an order of magnitude (10 times) to reduce brightness ripples.
  2. Guest Yuri
    #2 Guest Yuri Guests August 1, 2019 06:52
    0
    I converted a 12V screwdriver to work on mains power. I connect it to a homemade 14.5V charger. It works and whistles. I found on the Internet that you can reduce the voltage with a diode. Tell me the model or characteristics of the diode. I can’t choose something myself.
    1. Guest Alexey
      #3 Guest Alexey Guests 18 September 2019 19:20
      1
      set the bank to 8 b, and if the bank current is not enough, then through a transistor, you can get by with a transistor and a resistor.
  3. Evgeniy Parshin
    #4 Evgeniy Parshin Guests September 15, 2019 09:18
    1
    Let me explain briefly, an ordinary diode bridge, which can be taken from almost any modules that are powered by 220v, and a capacitor and resistor (resistance) is a shunt. The scheme is very correct and working, time-tested.
  4. Guest Palych
    #5 Guest Palych Guests 22 August 2021 17:00
    1
    Ahhh, I got it!!!! Judging by the hands, again the Indians are supposedly “inventing” something. Oh come on! They take these ideas from the Soviet YuT, TM, and MK. They themselves do not invent anything new. Even in this circuit, this poor guy managed to save on one resistance - another resistor of about 1-10 Ohms is needed in the power circuit to act as a fuse, or a fuse. It’s just that both the condenser and the matrix do not guarantee a banal breakdown, even from statics.
  5. Guest Palych
    #6 Guest Palych Guests 22 August 2021 17:04
    0
    In general, a mounted installation that GEOMETRICALLY repeats the schematic diagram is bad manners, a sign of poor taste and wretchedness of spatial thinking inherent in shkolota.

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